Help and maybe explain how to solve

1) x = 55°

2) x = 30°

3) x = 68°

Step-by-step explanation:

In the given set of questions where it requires to find the unknown value of x to prove that v ||w:

The Consecutive Interior Angles Theorem states that for any given two parallel lines cut by a transversal, the measures of a pair of consecutive interior angles have a sum of 180°. Hence, the pair of consecutive interior angles are supplementary.

1.)  In the given diagram, the two consective interior angles are m ∠70° and m ∠ 2x°.  As defined by the Consecutive Interior Angles Theorem:

m ∠70° + m ∠ 2x° = 180°

Solve for x algebraically:

70° + 2x° =  180°

Subtract 70° from both sides:

70° - 70° + 2x° =  180° - 70°

2x° =  110°

Divide both sides by 2 to solve for x:

x = 55°

Verify whether the value for x is valid:

70° + 2x° =  180°

70° + 2(55)° =  180°

70° + 110° =  180°

180° =  180° (True statement).

2) In the given diagram, the two consective interior angles are m ∠2x° and m ∠ 4x°.  As defined by the Consecutive Interior Angles Theorem:

m ∠2x° + m ∠ 4x° = 180°

Solve for x algebraically:

2x° + 4x° =  180°

Add like terms:

6x° = 180°

Divide both sides by 6 to solve for x:

x = 30°

The Consecutive Interior Angles Theorem still applies in this question. The two consective interior angles are m ∠90° and m ∠ (x + 22)°.  As defined by the Consecutive Interior Angles Theorem:

m ∠90° + m ∠ (x + 22)° = 180°

Solve for x algebraically:

90° + x° + 22 =  180°

Combine like terms:

112° + x° = 180°

Subtract 112° from both sides to isolate x:

112° - 112° + x° = 180° - 112°

x = 68°

Verify whether the value for x is valid:

90° + x° + 22 =  180°

90° + 68° + 22 =  180°

180° =  180° (True statement).

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

1e+27

step-by-step explanation: