Explain how you know if an equation has no solutions, one solution or an infinite number of solutions

If you cancel out all of the x terms via addition or subtraction, and you get something along the lines of 1 = 2, then you have no solution.

11x + 4 = 11x + 7 Subtract 11x from both sides

4 = 7 No value for x will satisfy this equation.

If you cancel out all the x terms via addition or subtraction and you get something along the lines of 1 = 1, then you have infinite solutions.

2(x + 1) = 2x + 2 Expand the left side using the distributive property

2x + 2 = 2x + 2 Subtract 2x from both sides

2 = 2 Every value for x will satisfy this equation

If you can’t cancel out all the x terms with addition or subtraction, you probably have 1 solution.

5x + 2 = 3x + 100 Subtract 3x from both sides

2x + 2 = 100 Subtract 2 from both sides

2x = 98 Divide by 2 on both sides

x = 49 The only x value that satisfies this equation is 49

There are other cases where functions of x aren’t injective, meaning there’s more than one x value that satisfies the equation. Here’s what I mean.

x^2 = 4

x = 2 or -2

x^3 = 1

x = 1, -1/2 + isqrt(3)/2, -1/2 - isqrt(3)/2

sin(x) = 0

x = 2n*pi, where n is some integer

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you