Create a quadratic function with an axis of symmetry x=3 whose graph opens down

f(x) = -2(x - 3)² - 1

Step-by-step explanation:

Every parabola is symmetric about its axis, which means that if it were folded along its axis, the two parts would match. Given x = 3 as the axis of symmetry, then it means that its vertex must have an h value of 3.

Using the vertex form of the quadratic function:

f(x) = a(x - h)²+ k

where:

a  determines whether the graph opens up or down.

(h, k) is the vertex  

Then, we can establish the following quadratic function using the vertex form:

f(x) = -2(x - 3)² - 1

The vertex of this quadratic function is (3, -1).

Attached is a screenshot of the given function.

Hope this helps :)      

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

hiking down a winding trail.

step-by-step explanation: