Water freezes at 32°F. The melting point of oxygen is -173F°. What is the difference between these two temperatures?

Step-by-step explanation:

A permanent marker

2 activity set-ups to use for demonstration purposes (One will be identical to the children's, the other will include all steps but salt will be omitted.1 thermometer that is easily read, preferably in both Celsius and Fahrenheit, and that is safe for use by children

1 (7-ounce) cup or larger plastic container

1 (8-ounce) clear plastic cup

Enough foil to cover the top — but not the sides — of the cup

~5 cups of ice cubes (not crushed ice) (Make sure the ice cubes are loose and not stuck together.)

1 cup of crushed ice

~2 cups of rock salt (the kind used to make ice cream)

1 timer, stopwatch, watch, or clock with a second hand

Paper TowelsWater can exist in different states; ice is the solid state of water.

Physical properties are characteristics of a substance. They do not change. Physical properties include color, smell, freezing/melting point, and density.

The freezing point of water is the same as the melting point of ice: 32°F (0°C).

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204