What is an
equation of the line that passes through the points (-4, -1) and (3,-8)?

y=-x-5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-(-1))/(3-(-4))

m=(-8+1)/(3+4)

m=-7/7

m=-1

y-y1=m(x-x1)

y-(-1)=-1(x-(-4))

y+1=-1(x+4)

y+1=-x-4

y=-x-4-1

y=-x-5

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hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8