PLEASE HELP!!
Algebra II

Hey there! :)

We are given the piecewise function:

To evaluate the value of function at x = -8 and x = 8, we know that -8 is less than 0 and 8 is greater than 0.

Therefore, if we want to evaluate the value of function at x = -8; we use the x^3 since it's given x < 0 for the function and for x = 8; we use the cube root of x since it's given x > 0.

Evaluate x = -8

From the piecewise function:

Since -8 is less than 0, we use x^3.

Evaluate x = 8

From the piecewise function, since 8 is greater than 0, we use the cube root of x.

To evaluate the cube root, first we prime-factor the number.

Since it's a cube root, we pull three 2's out of the cube root and write only one 2.

Answer

Let me know if you have any questions!

4400

step-by-step explanation:

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