A stunt car traveling at 20 m/s flies horizontally off a cliff and lands 39.2 m from the base of the cliff. How tall is the cliff?

18.82 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 20 m/s

Horizontal distance (s) = 39.2 m

Height (h) of the cliff =?

Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Horizontal distance (s) = 39.2 m

Time (t) taken to reach the ground =?

s = ut

39.2 = 20 × t

Divide both side by 20

t = 39.2 / 20

t = 1.96 s

Finally, we shall determine the height of the cliff as follow:

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) taken to reach the ground = 1.96 s

Height (h) of the cliff =?

h = ½gt²

h = ½ × 9.8 × 1.96²

h = 4.9 × 3.8416

h = 18.82 m

Therefore, the cliff is 18.82 m high

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.