![\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}](/tpl/images/1405/7524/679ad.png)
Please help me find limit
...
Mathematics, 07.08.2021 19:10 carolinasoto
Please help me find limit
Answers: 3
Other questions on the subject: Mathematics
Mathematics, 21.06.2019 18:00, edgarsandoval60
What is the equation of this graphed line? enter your answer in slope-intercept form in the box.
Answers: 2
Mathematics, 21.06.2019 23:40, Tabbicat021
If f(x) = -5x + 1 and g(x) = x3, what is (gºf)(0)? enter the correct answer
Answers: 1
You know the right answer?
Questions in other subjects:
Biology, 22.05.2020 21:04
Business, 22.05.2020 21:04
Mathematics, 22.05.2020 21:04
English, 22.05.2020 21:04
History, 22.05.2020 21:04
