In the figure above, the square ABCD is inscribed in a circle. if the radius of the circle is r, the hatbis the length of arc APD in terms of r? a) (pi)r/4
b) (pi)r/2
c) (pi)r
d) (pi)r^2/4

The length of arc APD is:

A square when inscribed in a circle will fit the circle such that, the 4 edges of the square touches the sides of the circle. The radius of the circle can be drawn from any of the 4 edges.

Given that ABCD is a square:

This means that:

--- equal side lengths

To calculate the length of arc APD, we make use of the following arc length formula

Where

and O is circle center

Since ABCD is a square, then:

So, we have:

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the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

1

step-by-step explanation:

you are throwing one dart