PLEASE HELP ME I WILL CHOOSE BRAINLIEST A bead is created from a sphere by drilling a cylinder through the
sphere. The original sphere has a radius of 8 mm. The cylinder drilled
through the center has a radius of 4 mm.
What is the height of the bead? (Hint: Draw a right triangle and use
the Pythagorean Theorem.)

Exact height = 8*sqrt(3) mm

Approximate height = 13.856 mm

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Explanation:

If you do a vertical cross section of the cylinder, then the 3D shape will flatten into a rectangle as shown in the diagram below.

After flattening the picture, I've added the points A through F

Those point labels will help solve the problem. We're told that the radius of the sphere is 8 mm. So that means segment AD = 8 mm.

Also, we know that FA = 4 mm because this is the radius of the cylinder.

Focus on triangle AFD. We need to find the height x (aka segment FD) of this triangle so we can then double it later to find the height of the cylinder. This in turn will determine the height of the bead.

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As the hint suggests, we'll use the pythagorean theorem

a^2 + b^2 = c^2

b = sqrt(c^2 - a^2)

x = sqrt(8^2 - 4^2)

x = sqrt(48)

x = sqrt(16*3)

x = sqrt(16)*sqrt(3)

x = 4*sqrt(3)

This is the distance from D to F

The distance from D to E is twice that value, so DE = 2*(FD) = 2*4*sqrt(3) = 8*sqrt(3) is the exact height of the bead (since it's the exact height of the cylinder).

Side note: 8*sqrt(3) = 13.856 approximately.

1/4 is the answer if i recall correctly.