The least value of x²-3x+5 is..​

11/4

Step-by-step explanation:

to find the minimum value we require to find the vertex and determine if max/min

for a quadratic in standard form ; ax² + bx + c

the coordinate of the vertex is..

xvertex = -b/2a

x² - 3x + 5 is in standard form with a = 1,b = - 3 and c = 5

xvertex = - , -3/2 = 3/2

substitute this value into the equation for y-coordinate

yvertex = ( 3/2 ) ² -3 (3/2) + 5 = 11/4

vertex = ( 3/2, 11/4 )

to determine whether max/min

• if a > 0 then minimum u

• ifa < 0 then maximum n

here a = 1 > 0 hence minimum

minimum value of x² - 3x + 5 is 11/4

hope you understand this :)

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

where is the figure