A hole of radius 2 inches is bored through the center of a right cylinder with radius 6 inches and height 10 inches. What is the total surface area of the resulting solid? Express your answer in terms of π.

184π in.²

Step-by-step explanation:

The total surface area of the resulting solid = the total surface area of the cylinder - the area of the two ends of the hole

✔️Total surface area of the cylinder = 2πr(r + h)

Where,

r = 6 inches

h = 10 inches

Total surface area of the cylinder = 2*π*6(6 + 10)

= 12π(16)

= 192π in.²

✔️Area of the two ends of the whole = 2(πr²)

Where,

r = 2 inches

area = 2(π*2²)

= 2(4π)

= 8π in.²

✔️The total surface area of the resulting solid = 192π - 8π

= 184π in.²

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step-by-step explanation: