Solve the simultaneous equation
2x-3y =8 x+3y=14
Use elimination method​​

x = 22/3  y = 20/9

Step-by-step explanation:

2x-3y =8 x+3y=14

Add the two equations together to eliminate y

2x-3y =8

x+3y=14

3x +0y = 22

Divide each side by 3

3x/3 = 22/3

x = 22/3

Then take the second equation and multiply by -2 and add to eliminate x

2x-3y =8

-2x-6y=-28

  -9y = -20

Divide by -9

-9y/-9 = -20/-9

y = 20/9

x = 22/3  y = 20/9

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!