Denise constructed the angle bisector of using the steps below. 1. Place your compass on vertex and open it any width. Swing an arc that
intersects both ray ED and ray EF
2. Label these points and respectively.
3. Place the compass on point G and open it to swing an arc inside angle DEF.
4. ?
5. Label the point of intersection as point I.
6. Draw a ray from the vertex through point I to create the angle bisector,

Which of the following is the missing step in her construction?
a. Place the compass on point I and swing an arc that intersects point H.
b. Place the compass on point E and swing an arc that intersects point I.
c. Leave the compass the same width and swing a second arc from point G to point H.
d. Place the compass on point Hand, using the same width as previous step, swing an arc
that intersects the arc created in step 3.

neither i nor ii 56 / 4.9 = 11.91489362 and 82 / (11+5) =5.125 so i is wrong

ii. (24/8+2) times 3 = 15 and (42+9)/2 =25.5

step-by-step explanation:

56

5.6%

step-by-step explanation:

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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