A bal will be thrown upward from a height of 20 meters above the ground with an initial velocity of 15 meters per second. Its distance from the ground. d. is a function of the time in seconds since the ball was thrown, L. This function is graphed below
Ball's Distance from
Ground over Time
Distance from Ground
(motora)

How many seconds after the ball is thrown will it be 20 meters from the ground again?

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

sure i'm up for it

step-by-step explanation:

mujhko hui na

hello there,

to convert kg to pounds and ounces you set up

turn the kg into

8.3/x = 1/2.2

x = 18.26

now convert the pounds into

18.26/x = 1/16

x = 292.16

now that is the answer in ounces.

answer: 18.26 lb; 292.16 oz

hope i

-char