Two quadratic equations are shown below. • Equation 1: y = x2
Equation 2: y = -2° + 2
Which series of transformations would carry the graph of Equation 1 onto the graph of Equation 2?
A
reflection across the y-axis followed by a horizontal shift 2 units to the left
B
reflection across the x-axis followed by a vertical shift up 2 units
С
reflection across the x-axis followed by a horizontal shift 2 units to the left
D
reflection across the y-axis followed by a vertical shift up 2 units

-2 is the right

3 is greater then both of those numbers

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form