5pennies ,3 dimes and 4 quarters are placed in a bag .what is the probability of selecting a quarter and then another quarter, given the first coin is not returned to the back after it is drawn? a. 2/11 b. 1/11 c. 1/22 d. 5/33

5+3+4 = 12 total coins

4 are quarters so first selection = 4/12 reduces to 1/3

after taking a coin out there would be 11 coins left and 3 quarters left

 so 2nd selection would be 3/11

now multiply 3/11 x 1/3 = 3/33 which reduces to 1/11

B. 1/11 is the correct answer

just needed some points but try socratic

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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