The axis of symmetry for a function in the form f(x) = x2 + 4x − 5 is x = −2. what are the coordinates of the vertex of the graph?
(−9, −2)
(−17, −2)
(−2, −17)
(−2, −9)

Option D

Step-by-step explanation:

The given function is f(x) = x² + 4x - 5

Axis of symmetry is x = -2

Since axis of symmetry of a quadratic function passes through the vertex so x = -2 will be the x-coordinate of the vertex.

We will now convert the given function into vertex form.

Where (h, k) are the coordinates of the vertex

f(x) = x² + 4x - 5

     = x² + 4x + 4 - 4 - 5

f(x) = (x + 2)² - 9

Therefore, the vertex will be (-2, -9)

Option D will be the answer.

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5