Slope-intercept form hw i'm not sure how to do this just with 1 and i can get the rest by example

The equation of a line is written as y=mx+b where m is the slope and b is the y-intercept.
To find slope use the equation m=y sub 2 - y sub 1 / x sub 2 - x sub 1
Your two points are (-2,3) and (0,0)
M=0-3/0-(-2)
M=-1.5
Y=-1.5x+3
Y=-1.5x+0 this is parallel to y=-1.5x+3

Ok, for a slope intercept equation you need the form y=mx+b
where m is the slope (rise/run) and b is the y intercept.  I don't see the equations you have, but I'll try to explain how to do it.
The slope of a parallel line will have the same slope as the line of the original plot and will pass through the given point.  To get the slope of an equation, just look at what number is multiplied by x.  If you only have a plot (no equation), count how many tick marks the line goes up (or down) when you move right on the x axis.  Sometimes you have to move over a few marks on x to get a whole number of steps on y.  So if you go over 3 'x' marks to go up 2 'y' marks, the slope is 2/3.  If you go down by 5 on the y axis when you go over 2 'x' marks, its -5/2. It's always in the form y/x.  To get the final equation, you still need the y intercept, b.  To get this use the point given and set the equation equal to the y coordinate, the x equal to the x coordinate and use the slope you found.  Then solve for b.  For example let's say your slope was 5 on the first problem, with the point (-2, 3).  Then to get the value of b in the equation y=mx+b, you would write 
3 = 5(-2) + b   (I plugged in your pair (x,y) of x=-2 and y=3 into y=mx+b)
3 = -10 + b
13 = b
then your equation is y = 5x + 13
For perpendicular lines the slope is the negative reciprocal of the parallel line slope.  So in the above example of a slope of 5 for a parallel line, the perpendicular line's slope is -1/5.  The negative sign and reciprocal are both needed.  Then find the value of b the same way I showed above (it will be different than the parallel line)
Hope this explanation helps.