Arectangle has a perimeter of 64 inches and a length of 22 inches. which equation can you solve to find the width?

a. 64 − w = 44

b. 2w + 44 = 64

c. 2w + 22 = 64

d. 22 + w = 64

It's B because if one length is 22 then both lengths combined is 44 + the width. Since there are 2 of those, each are represented with w so basically you're adding 2w to the total length,44 which will end up to look like 44+ 2w

Perimeter is found by the formula 2l+2w, where l is the length and w is the width. 

Since we have a length of 22 inches and a perimeter of 64 inches, the width can be found by solving the equation 2(22)+2w=64, or 2w+44=64.

:)