Two less than three times the width of a rectangle is equal to the length. the area of the rectangle is 65 square ft. what is the length of the rectangle? a) 9 feet b) 11 feet c) 13 feet d) 20 feet

Option C - 13 feet.

Step-by-step explanation:

Given : Two less than three times the width of a rectangle is equal to the length. The area of the rectangle is 65 square ft.

To find : What is the length of the rectangle?

Solution :

The area of the rectangle is given by,

The area of the rectangle is 65 square ft.

Let the width of the rectangle be 'w'.

Two less than three times the width of a rectangle is equal to the length.

The length of the rectangle is l=3w-2

Substitute the value in the formula,

Applying quadratic formula,

The width of the rectangle is 5 ft.

The length of the rectangle is l=3w-2=3(5)-2=13 ft

Therefore, Option C is correct.

$35.59 in pounds

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?