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Mathematics, 08.08.2019 03:10 elielson1497

For k = {(x, y) | x - y = 5}, and the domain of x = 0, 2, 4
select the graph that represents the set of data. (click on the graph until the correct one is showing.)


For k = {(x, y) | x - y = 5}, and the domain of x = 0, 2, 4 select the graph that repres

Answers

ansver
Answer from: chrisgonzv1219
1. no
2.a,e
3.b.{0, 2, 4}
4.Yes
5.No
ansver
Answer from: giraffesaur44
1.

The description of set K as  {(x, y) | x - y = 5}, means the following:

the elements of set K are pairs (x,y)

such that:  x-y=5, that is we can write(x, y) = (x, x-5).

2.

A set of (ordered) pairs is a function, if each of the first coordinates is paired to only 1 specific value, not 2 or more.

for example: {(1,2), (3, 5), (3, 8)} is not a function because 3 is not paired to only one second value, we have (3, 5) but also (3, 8).

whereas, {(-2, 4), (3, 5), (8.1, 17)} is a function, because each first coordinate is unique, we don't see it again in another pair.   

3.

Back in our set K, the description of pairs (x,y) as (x, x-5)

makes sure that each x, produces a specific y, for example in K we have:

(5, 0), and we cannot have (5, a value ≠0), because it would not fit the description (x, x-5)

yes
ansver
Answer from: owenbarrows

Yes, because the linear function  x - y = 5 is a function

Step-by-step explanation:

x - y = 5  can look like   y = x - 5  with slope 1 and y-intercept -5

so this is a function  which makes set K a function.

ansver
Answer from: underfellrocks

Yes, set K is a function.

Step-by-step explanation:

Given K = {(x, y) | x - y = 5}

we have to find is above set is a function or not.

Functions are relations that give one output for each input, or one x- value gives only one value of y.

As, x-y=5

⇒ y=x-5

The above set is a function because every x-value produces a different y-value i.e K satisfies the definition of what it meant for a relation to be  function.

Hence, set K is a function.

ansver
Answer from: rscott400
No, That’s not a function.
ansver
Answer from: pronces
Yes it is young master

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For k = {(x, y) | x - y = 5}, and the domain of x = 0, 2, 4
select the graph that represents t...

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