Jacob is training for a marathon. his plan is to run the same distance for 3 days a week, then increase that distance by the same amount each week of training. during week 6, jacob runs 14 miles per day, which is 1.5 miles more per day than he ran during week 5. which equation represents the daily running distance, in miles, as a function of time, t, in weeks?
a. f(t) = 0.5t + 7
b. f(t) = 0.5t + 11
c. f(t) = 1.5t + 5
d. f(t) = 1.5t + 12.5

Given:
Week 6 = 14 miles
Week 5 = 1.5 miles less than week 6.

1.5 miles is the common difference.

Week 6 = 14 miles
Week 5 = 12.5 miles
Week 4 = 11 miles
Week 3 = 9.5 miles
Week 2 = 8 miles
Week 1 = 6.5 miles

f(t) = first term + common difference(t-1)
f(t) = 6.5 miles + 1.5 miles (t-1)

f(1) = 6.5 + 1.5(1-1)
f(1) = 6.5 miles

f(2) = 6.5 + 1.5(2-1)
f(2) = 6.5 + 1.5
f(2) = 8 miles

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )