Gabriella needs a mason and must decide between 2 companies. for a service visit, company a charges $65 to send a mason plus $30/h. company b charges $30
to send a mason plus $47.50/h. the graph that models this situation is shown here.

according to the graph, how many hours must the two masons work in order to charge the same amount of money?

hour(s)

So first we write out their respective charges
A=65+30x (x=hours of A)
B=30+47.5y (x= hours of B)

we want to know when A and B are equal so just set them to be equal

65+30x=30+47.5x
subtract 30 from both sides
35+30x=47.5x
multiplyboth sides by 2 to get rid of the nasty decimal
70+60x=95x
subtract 60x from both sides
70=35x
divide both sides by 35
2=x
they must work 2 hours for them to be equal

By looking at were the two lines meet on the graph, they would both have to work for 2 hours to charge the same.

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!