Afrog fell into a hole that was 14 ½ feet deep. he could jump 3 feet, but he slid back a foot each time he jumped. how many jumps does it take him to get out of the hole?

Basically, the frog only jumps two feet every time, so he would need 8 jumps, because there was still that extra 1/2 of a foot.

The answer is 7 jumps.

The solution to the problem is as follows:
The frog advances 2 feet with each jump, but he jumps 3 feet, so the 7th jump, starting at 12 feet, brings him to 15 feet, which takes him out of the hole." 

In other words, each time he jumps, and it took him 7 jumps to get out of the whole, as on the 6th jump he was able to get 12 ft high, and on the 7th he got 15 ft high, 1/2 feet over the hole, so he doesn't slid back a foot. 

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i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5

Idon't know what's the answer lol