Once I get it wrong, I can’t redo the same question again and I have to go onto the next question. I only have 5 questions but if I get 1 wrong I have to keep on answering questions til I get 5 questions right. So far I got 4 out of 5 correct. So someone please help me. I’ve been trying to get 5 questions correct all day. This question is worth 50 points

Step-by-step explanation:

Hello There!

Once again here are the Trigonometric Ratios

Sin = opposite divided by hypotenuse

Cos = adjacent divided by hypotenuse

Tan = opposite divided by adjacent

We need to find the measure of angle O

We are given the opposite side length (89) and the adjacent side length (74)

This corresponds with tangent so we are going to use tangent to solve for x

Now we create an equation: (remember tangent = opposite divided by adjacent)

now we have

once again we want to isolate the variable (x)

To do so we need to get rid of tan by taking the inverse of tan (arctan^-1) and applying that to each side

finally we want to round to the nearest tenth

50.25

its a five so we raise the 2 to a 3

and we're left with

x = 50.3

answer: sorry i can't you.

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!