Factor: 3bc-4ad +6ac-2bd
Can you create a rubric for this math question

3bc - 4ad + 6ac - 2bd

= 3bc – 2bd - 4ad + 6ac rearrange the terms

= b(3c – 2d) – 2a(2d – 3c)

(3c−2d)(2a+b)

Step-by-step explanation:

3bc−4ad+6ac−2bd

Do the grouping 3bc−4ad+6ac−2bd=(6ac−4ad)+(3bc−2bd), and factor out 2a in the first and b in the second group.

2a(3c−2d)+b(3c−2d)

Factor out common term 3c−2d by using distributive property.

(3c−2d)(2a+b)

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )