There are 3 roses, 4 tulips, 1 carnation and 4 irises. One flower is taken out of the box. What is the probability that a rose, then a tulip, then a carnation is selected?

the answer is a reflection across the line m

step-by-step explanation:

on edge

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the answer

b. they are parallel and will never intersect.

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation: