Triangle ABC has vertices A(0,2), B(5,4), and C(5, O). Triangle A'B’C’ has corresponding vertices A' (-5, -1), B’ (0, 1), and C’ (0, -3). Which of the following
describes a translation that would produce triangle A'B'C’ from the pre-image of
triangle ABC?
A) To the left five units, up three units.
B) To the right five units, down three units.
C) To the left five units, down three units.
D) To the right five units, up three units.

the 3rd on is correct

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

step-by-step explanation: