1. According to Health (May/June 1993, p. 12), 24% of all births in the United States in 1993 were by Caesarean section. If 500 births that occurred in the United States
during 1993 are randomly selected, what is the probability that at most 100 of them
were by Caesarean section?

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.

step-by-step explanation:

1 mph

step-by-step explanation:

if the question is asking how much does she drive per mile then,

13 / 13 = 1 mph