The thickness (in millimeters) of the coating applied to hard drives is one characteristic that determines the usefulness of the product. When no unusual circumstances are present, the thickness (x) has a normal distribution with a mean of 2 mm and a standard deviation of 0.04 mm. Suppose that the process will be monitored by selecting a random sample of 25 drives from each shift's production and determining x, the mean coating thickness for the sample. Required:
Describe the sampling distribution of X (for a sample of size 16).

The sampling distribution of X, for a sample of size 16, will be approximately normal with mean 2 mm and standard deviation 0.01 mm.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For the population:

Mean 2 mm, standard deviation 0.04 mm

Describe the sampling distribution of X (for a sample of size 16).

Sample of size 16 means that

By the Central Limit Theorem, approximately normal with mean 2 and standard deviation

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

-2 is the right