Mathematics, 23.01.2021 16:00 dtilton2003

1. The vertex of a parabola is at (12, -4), and its axis of symmetry is vertical. One of the x-intercepts is at (15, 0). What is the x-coordinate of the other x-intercept? 2. Find the equation of the axis of symmetry of the graph of y = (x + 3)^2 - 5.

3. The x-intercepts of the parabola y = x^2 + bx + c are (-3,0) and (5,0). Find the equation of the parabola, and submit your answer in y = ax^2 + bx + c form.

4. Find the equation of the axis of symmetry of the parabola. (attachment below)

Thank you

1. The vertex of a parabola is at (12, -4), and its axis of symmetry is vertical. One of the x-inte

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1. The vertex of a parabola is at (12, -4), and its axis of symmetry is vertical. One of the x-inter...