What is the equation of the line that passes through the point (-5, -4) and has a slope of – 3/5?

             y + 4 = -³/₅(x + 5)      {the point-slope form of the equation }

             y = -³/₅x - 7               {the slope-intercept form of the equation}

             3x + 5y = - 35               {standard form of the equation}

Step-by-step explanation:

The point-slope form of equation is : y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through.

m = -³/₅

(-5, -4)    ⇒   x₀ = -5,  y₀ = -4

Therefore:

y - (-4) =  -³/₅(x - (-5))

y + 4 = -³/₅(x + 5)      ←  the point-slope form of the equation

y + 4 = -³/₅x - 3              {subtract 4 from both sides}

y = -³/₅x - 7               ←  the slope-intercept form of the equation

³/₅x + y = - 7                     {multiply both sides by 5}

3x + 5y = - 35               ←  standard form of the equation

step-by-step explanation:

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