1 Mary and Darryl are selling flower bulbs for a school fundraiser. Customers can buy bags of

windflower bulbs and bags of daffodil bulbs. Mary sold 10 bags of windflower bulbs and 4

bags of daffodil bulbs for a total of $226. Darryl sold 6 bags of windflower bulbs and 4 bags of

daffodil bulbs for a total of $166. What is the cost each of one bag of windflower bulbs and

one bag of daffodil bulbs?

15 windflower bulbs

19 daffodil bulbs

Step-by-step explanation:

Given

Represent windflower with W and daffodil with D.

So:

Mary's sales is:

10W + 4D = 226 --- (1)

Darryl's sales is:

6W + 4D = 166 (2)

Required

Solve for W and D

We'll make use of elimination method.

Start by subtracting (2) from (1)

10W - 6W + 4D - 4D = 226 - 166

4W = 60

Multiply both sides by ¼

¼ * 4W = 60 * ¼

W = 60 * ¼

W = 15

Substitute 15 for W in (1)

10W + 4D = 226

10 * 15 + 4D = 226

150 + 4D = 226

Collect like terms

4D = 226 - 150

4D = 76

Multiply both sides by ¼.

¼ * 4D = 76 * ¼.

D = 19

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3