Which of the following has the least value? A. 13/15
B. 7/8
C. 2/3
D. 3/4

(I also need the work if not its ok!)

C. 2/3

Step-by-step explanation:

To solve this, we should come up with a common denominator first.

The least common denominator (LCD) of the four fractions would be 120.

So, first multiply each fraction's denominator to get 120, and multiply the numerator by the same amount.

ex. 3/4

4 x 30 = 120

3 x 30 = 90

We get 90/120.

After doing this with each fraction, we get;

13/15 = 104/120

7/8 = 105/120

2/3 = 80/120

3/4 = 90/120

Now, it is easier to see which fraction has the least value (or the one that is the smallest. Your answer is 2/3, since 80/120 is the smallest out of the four.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the line of