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The sum of three numbers is 56. If the second number is equal to the first diminished by 4, and the third number is 3
times the first. What are the numbers?
If x represents the first number, then which of the following equations could be used to solve the problem?
x = 3x-4
56=4x4
56=3x-4
56-5x4
a
OX
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Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.

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