Given: AE= 7 5/8cm, AB=BC, CD= 1/2cm, and DE is 3/8 more than AB. What is the length of DE?

Length of DE = 2.90 (Approx)

Step-by-step explanation:

Given:

AE = 7cm = 61 / 8 cm = 7.625 cm

AB = BC

CD = 1/2 cm = 0.5 cm

DE is 3/8 more than AB

Find:

Length of DE

Computation:

Assume;

AB = BC = x

So,

DE = x + 3/8(x) = [11 / 8]x = [1.375]x cm

AE = AB + BC + CD + DE

7.625 = x + x + 0.5 + [1.375]x

7.125 = 3.375 x

x = 2.1111 (Approx)

Length of DE = [1.375][2.111]

Length of DE = 2.90 (Approx)

a - base

b - exponent

so,