4) Three standard basis vectors are noted as p = 3i + 2k, q = 4i – 2; +3k and r= -3i + 5j - 4k. Solve for :
i)
3p + 2q + 3r

ii)
10p + 74 + 8r

i) 3p+2q+3r = 8i+11j

ii) 10p + 7q + 8r= 34i+26j+9k

Step-by-step explanation:

We are given vectors

p = 3i + 2k, q = 4i – 2j +3k and  r= -3i + 5j - 4k

Note: There is typing mistake in q=4i-2;+3k there should be j instead of ; i.e 4i – 2j +3k

We need to find

i) 3p+2q+3r

Putting values of p, q and r

So, 3p+2q+3r = 8i+11j

ii) 10p + 7q + 8r

Note: Considering 7q instead of 74

So, 10p + 7q + 8r= 34i+26j+9k

idk

step-by-step explanation: i just don't

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right