Max tosses a fair coin 3 times what is the probability of getting heads in the first two trials and tails in the last trial

.5 * .5 *.5 = 1/8 
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the probability to have head is .5 so the probability of tails 1-.5 
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then the first time is head  
the second time is head 
the third time is tail 
so 
.5 * .5 *.5 = 1/8 

First of all, we know that the coins has 2 side - head and tail. And the probability of tossing and get head or tail is 50/50 or 1/2.
Next,
P(getting a head in the first toss):
1/2
P(getting a head in the second toss):
1/2
P(getting a tail in the last toss):
1/2, so the probability of getting heads in the first two trials and Tails in the last trial is 1/2×1/2×1/2 or 1/8 is your final answer. Hope it help!

The operation is suck a c@ck? !

Answers: the graph is translated down 1 unit and the domain and range of g(x) is the same as the domain and range of f(x).