A shop owner can buy two televisions and three DVD players for $1750 or four televisions and one DVD players for $1250. Find the cost of one of each

Television = $200 and DVD player = $450

Step-by-step explanation:

→ Make 2 equations

Televisions = t and DVD players = d

2t + 3d = 1750

4t + d = 1250

→ Multiply the bottom equation by 3 to make the same variable of d

2t + 3d = 1750

12t + 3d = 3750

→ Minus the two equations to isolate the d variable

-10t = -2000

→ Divide both sides by -10 to find the cost of one television

t = 200

→ Substitute t = 200 back into 4t + d = 1250

800 + d = 1250

→ Minus 800 from both sides to isolate d

d = 450

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3