The measure of <ACD is 120. Find the measure of <ACB, <BCD, and <ACE. Explain how you found the measure of <ACE.

m∠ACB = 39°

m∠BCD = 81°

m∠ACE = 60°

Step-by-step explanation:

From the picture attached,

m∠ACD = 120°

Since, m∠ACD = m∠ACB + m∠BCD

x + (2x + 3) = 120°

3x + 3 = 120

3x = 117

x = 39

Therefore, m∠ACB = 39°

m∠BCD = (2x + 3) = 2(39) + 3

             = 81°

Since, m∠ACE +  m∠ACB + m∠BCD = 180° [Angles formed at a point on a straight line]

m∠ACE + 39 + 81 = 180

m∠ACE = 180 - 120

m∠ACE = 60°

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

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step-by-step explanation: