Jay and Pete are running in a race. At 9am Jay was 15 ft ahead of Pete, at 10am Pete was ‘f' ft ahead of Jay. Write an expression that shows how many more ft Pete ran than Jay between the hours of 9am and 10am?

(15 + f) feets

Step-by-step explanation:

Given that:

Race between Jay and Pete:

Let ;

distance covered by Jay = j

Distance covered by Pete = p

At 9:00a.m :

Jay was 15 feet ahead of Pete

Hence,

j - p = 15 feet

At 10 a.m :

Pete was 'f' feet ahead of Jay:

p - j= f feets

Number of feets Pete ran than Jay between 9 to 10 a. M

f feets + number of feets at which Pete was being Jay at 9a.m

f feets + 15 feets = (15 + f) feets

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i dont know

step-by-step explanation: