What is the equation of the line that passes through the points (-6,-7) and (6,3)

Step-by-step explanation:

Point-slope form:

where are coordinates of a point that the line passes through, and is the slope of the line.

We are given two points that the line passes through, but we are not given the slope.

We can find the slope by using the slope formula:

where and are two points that the line passes through.

Substitute (-6, -7) and (6, 3) into the slope formula:

The slope of this line is 5/6. Now we are able to use the point-slope equation to find the slope-intercept equation of this line.

Substitute a point that the line passes through and the slope of the line into the point-slope equation. I'm using the point (6, 3).

Distribute 5/6 inside the parentheses.

Add 3 to both sides of the equation.

This is the equation of the line that passes through (-6, -7) and (6, 3) in slope-intercept form.

765238725478629038640962136509762139056074

step-by-step explanation:

64087235609746097215074621039754021037

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!