Help rn

factorise 3x^2 + 20x + 12

Step-by-step explanation:

Use the reverse FOIL method:

_

We can check our work by using the actual FOIL method:

FOIL:

Combine like terms:

(3x+2)(x+6)

Step-by-step explanation:

The thing below shows how I used the factors of 3 from 3x (3 and 1) and the factors of 12 from, well, 12 (2 and 6)

3        2

1         6

By cross multiplying 3 and 6 you get 18, and if you multiply 2 and 1 together you get two. By adding these two together you get 20, which you must get in order to get the 20 of 20x. And since none of the numbers above are negative, you write the first row (3 and 2) as 3x+2, and the second row (1 and 6) as x+6. FINALLY, by putting 3x+2 and x+6 in parentheses, you'll get (x+6)(3x+2), or (3x+2)(x+6). Either of these will work :D.

idk

step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions