What is the equation of a line passing through the point (4,-1) and parallel to the line whose equation is 2y-x=8

9514 1404 393

  2y -x = -6

Step-by-step explanation:

You can use the same x- and y-coefficients. You just have to change the constant on the right. Put the point values into the left expression to see the new constant.

  2y -x = 2(-1)-(4) = -6

The parallel line is ...

  2y -x = -6

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

on your paper it doesn't say the answer but the the answer is altitude

step-by-step explanation: