How do you do this question?

bn = 1 / n

Step-by-step explanation:

We want to show the series an diverges.  So we need to find a smaller function bn that diverges.  That means we can eliminate options C and D, both of which converge.

an = (3 + sin(n) + e⁻ⁿ) / (2n − 1)

Sine is between -1 and +1, and e⁻ⁿ  approaches 0 as n approaches infinity.  So the numerator is a minimum of 2 as n approaches infinity.  So we can make a new function:

an = 2 / (2n − 1)

Let's look at option B: bn = 4 / √n = 2 / (½√n).

½√n is less than 2n − 1, so bn is greater than an.  We can't use that to show that an diverges.

Now let's look at option A: bn = 1 / n = 2 / (2n).

2n is greater than 2n − 1, so bn is less than an.  Since bn diverges, an must also diverge.

i think this could be a possible answer (1 / 84) -1

good luck! : d

vbbv

step-by-step explanation: