f Khan had an army of 10,000 soldiers at the lowest level, how many men in total were under him in his organization? (b) If Khan had an army of 5763 soldiers at the lowest level, how many men in total were under him in his organization? Assume that the groups of 10 should contain 10 if possible, but that one group at each level may need to contain fewer.

This question is incomplete, the complete question is;

Genghis Khan organized his men into groups of 10 soldiers undera“leader of 10.” Ten “leaders of 10”were undera“leader of 100.” Ten “leaders of 100”were undera“leader of 1,000.”

(a) If Khan had an army of 10,000 soldiers at the lowest level, how many men in total were under him in his organization?

(b) If Khan had an army of 5,763 soldiers at the lowest level, how many men in total were under him in his organization?

Assume that the groups of 10 should contain 10 if possible, but that one group at each level may need to contain fewer

a) = 11110 soldiers

b = 6404 soldiers

Step-by-step explanation:

Given that Khan arranged his men in to groups  of 10 soldiers under a "leader of 10" Ten" leaders of 10 were under a "leader of 100." Ten" leaders of 100" were under a "leader of 1000"

so

a) If Khan had an army of 10,000 soldiers at the lowest level, how many men in total were under him in his organization?

NOW

Number of soldier = 10,000

Lower Rank (soldier) = 10000

third highest  (leader of 10) = 10000/10 = 1000

second highest ( leader of 100) = 1000/10 = 100

Highest ranked ( Leader of 1000) = 100/10 = 10

so the Total = 10000 + 1000 + 100 + 10 = 11110 soldiers

b) If Khan had an army of 5,763 soldiers at the lowest level, how many men in total were under him in his organization? Assume that the groups of 10 should contain 10 if possible, but that one group at each level may need to contain fewer

NOW

Number of soldiers = 5,763

Lowest Rank (soldier) = 5763

third highest  (leader of 10) = 5763/10 = 576.3 = 577 (whole number required for human)

second highest ( leader of 100) = 577/10 = 57.7 = 58

Highest ranked ( Leader of 1000) = 58/10 = 5.8 = 6

so the Total = 5763 + 577 + 58 + 6 = 6404 soldiers

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.