For the given function, identify the x- and y-intercepts if any, the vertex, the axis of symmetry, and the maximum or minimum value. f(x)=−x2+25 A) There are no x-intercepts. The y-intercept is (0,25). The vertex is (0,25). The axis of symmetry is y=0. The maximum value of the function is 25. B) The x-intercepts are (−5,0) and (5,0). The y-intercept is (0,25). The vertex is (0,25). The axis of symmetry is x=0. The maximum value of the function is 25. C) The x-intercepts are (−5,0) and (5,0). The y-intercept is (0,−25). The vertex is (0,−25). The axis of symmetry is x=0. The minimum value of the function is −25. D) The x-intercepts are (−25,0) and (25,0). The y-intercept is (0,5). The vertex is (0,5). The axis of symmetry is x=0. The maximum value of the function is 5.

B) The x-intercepts are (−5,0) and (5,0). The y-intercept is (0,25). The vertex is (0,25). The axis of symmetry is x=0. The maximum value of the function is 25.

Step-by-step explanation:

Given that the function is:

It is quadratic equation, therefore we can observe that it is a parabola.

The coefficient of is negative, therefore it opens downwards.

That means it will have a maximum value.

This maximum value is at the vertex and where x = 0.

Also, vertex is at x intercept.

x intercept is the value of x where we have y = 0 and

y intercept is the value of y where we have x = 0

So, let us put y = 0 first.

Therefore x intercepts are at (5, 0) and (-5, 0)

Now, let us put x = 0,

Therefore y intercept is at (0, 25).

It is the point of maximum value (which is 25) and vertex of parabola as explained above.

Kindly refer to the attached image for the graph of given function.

Therefore, correct option is:

B) The x-intercepts are (−5,0) and (5,0). The y-intercept is (0,25). The vertex is (0,25). The axis of symmetry is x=0. The maximum value of the function is 25.

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents