In most geometry courses, we learn that there's no such thing as "ssa congruence". that is, if we have triangles abc and def such that ab=de, bc=ef, and ∠a=∠d, then we cannot deduce that abc and def are congruent. however, there are a few special cases in which ssa "works". that is, suppose abc is a triangle. let ab=x, bc=y, and ∠a=θ. for some values of x, y, and θ, we can uniquely determine the third side, ac.(a) use the law of cosines to derive a quadratic equation in ac.(b) use the quadratic polynomial you found in part (a) in order to find conditions on x, y, and θ which guarantee that the side ac is uniquely determined.

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft