Pablo started with line A B ↔ AB A, B, with, \overleftrightarrow, on top and point C CC and constructed F G ↔ FG F, G, with, \overleftrightarrow, on top through point C CC. A A B B C C E E D D F F G G Which two statements, if true, guarantee that F G ↔ FG F, G, with, \overleftrightarrow, on top is perpendicular to A B ↔ AB A, B, with, \overleftrightarrow, on top?

ou would have 12 of each

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

i saw this question before, dont know the asnwer srry

step-by-step explanation: